(4x+2)=(6x^2-x+2)

Solution for (4x+2)=(6x^2-x+2) equation:

(4x+2)=(6x^2-x+2)

We move all terms to the left:

(4x+2)-((6x^2-x+2))=0

We get rid of parentheses

4x-((6x^2-x+2))+2=0


We calculate terms in parentheses: -((6x^2-x+2)), so:

(6x^2-x+2)

We get rid of parentheses

6x^2-x+2

We add all the numbers together, and all the variables

6x^2-1x+2

Back to the equation:

-(6x^2-1x+2)


We get rid of parentheses

-6x^2+4x+1x-2+2=0

We add all the numbers together, and all the variables

-6x^2+5x=0

a = -6; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-6)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-6}=\frac{-10}{-12}
=5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-6}=\frac{0}{-12}
=0
$